If A and B are two square matrices of the same order then `(A-B)^2` is (A) `A^2-AB-BA+B^2` (B) `A^2-2AB+B^2` (C) `A^2-2BA+B^2` (D) `A^2-B^2`

If A and B are square matrics of the same order then (A-B)^2=?

If A and B are square matrics of the same order then (A+B)^2=?

If A and B are square matrices of order 2, then (A+B)^(2)=

If A and B are symmetric matrices of same order, then AB - BA is a :

If A and B are square matrices of the same order such that (A + B) (A - B) = A^2-B^2, then (ABA^-1)^2 =

If A and B are square matrices of the same order such that B=-A^(-1)BA, then (A+B)^(2)

If A,B are symmetric matrices of same order, then AB-BA is a :

If A and B are square matrices of the same order,then (A+B)(A-B) is equal to A^(2)-B^(2)(b)A^(2)-BA-AB-B^(2)(c)A^(2)-B^(2)+BA-AB(d)A^(2)-BA+B^(2)+AB

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies (A) AB=0 (B) AB+BA=0 (C) AB=BA (D) none of these

If A and B are square matrices of the same order such that AB=BA, then (A) (A-B)(A+B)=A^2-B^2 (B) (A+B)^2=A^2+2AB+B^2 (C) (A+B)^3=A^3A^2B+3AB^2+B^3 (D) (AB)^2=A^2B^2