Find the consecutive terms in the binomial expansion oif `(3+2x)^7` whose coefficients are equal

Find the two consecutive terms in the expansion of (3+2x)^(74) so that the coefficients of powers of x are equal.

Ratio Of Consecutive Terms In Binomial Expansion

Find the two consecutive cocfficients in the expansion of (3x-2)^(75) whose values are equal

Two consecutive terms in the expansion of (3+2x)^74 have equal coefficients then term are (A) 30 and 31 (B) 38 and 39 (C) 31 and 32 (D) 37 and 38

Find the 10 th term in the binomial expansion of (2x^(2)+(1)/(x))^(12)

For beta ne 0 , if the coefficient of x^(3) in the binomial expansion of (1 + betax)^(6) and the coefficient of x^(4) in the binomial expansion of (1 - betax)^(8) are equal, then the value of beta is

If the ratio of coefficients of the three consecutives terms in binomial expansion of (1+x)^(n) is 2:5:70. Then the average of these coeficients is

The sum of the coefficients in the binomial expansion of (1/x +2x)^6 is equal to :

If for some positive integer n, the coefficients of three consecutive terms in the binomial expansion (1+x)^(n+5) are in the ratio 5:10:14 , then the largest coefficient in this expansion is :