A particle starts from the origin, goes along the X-axis to the pont (20m, 0) and then returns along the same line to the point (-20m,0). Find the distance and displacement of the particle during the trip.

Explanation

To solve the problem, we need to find both the distance and displacement of the particle during its trip. Let's break it down step by step.

### Step 1: Understand the Motion of the Particle
The particle starts at the origin (0, 0) and moves to the point (20 m, 0) along the X-axis. After reaching (20 m, 0), it returns back along the same line to the point (-20 m, 0).

### Step 2: Calculate the Total Distance Traveled
1. **From the Origin to (20 m, 0)**: The particle travels 20 meters.
2. **From (20 m, 0) back to the Origin (0, 0)**: The particle travels another 20 meters.
3. **From the Origin (0, 0) to (-20 m, 0)**: The particle travels 20 meters again.

Now, we can sum these distances:
- Distance from (0, 0) to (20, 0) = 20 m
- Distance from (20, 0) to (0, 0) = 20 m
- Distance from (0, 0) to (-20, 0) = 20 m

**Total Distance = 20 m + 20 m + 20 m = 60 m**

### Step 3: Calculate the Displacement
Displacement is defined as the shortest straight-line distance from the initial position to the final position, along with its direction.

1. **Initial Position**: (0, 0)
2. **Final Position**: (-20, 0)

To find the displacement:
- The displacement vector can be calculated as:
\[ \text{Displacement} = \text{Final Position} - \text{Initial Position} = (-20, 0) - (0, 0) = (-20, 0) \]

The magnitude of the displacement is 20 meters, and since the final position is to the left of the origin, the direction is in the negative X direction.

### Final Answers
- **Total Distance Traveled**: 60 meters
- **Displacement**: 20 meters in the negative X direction