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A small block of mass 100 g is pressed a...

A small block of mass 100 g is pressed again a horizontal spring fixed at one end to compress the sprign through 5.0 cm. The spring constant is 100 N/m. When released, the block moves hroizontally till it leaves the spring. Where will it hit the ground 2 m below the spring?

Text Solution

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The correct Answer is:
A, C, D

`m=100 g=0.1 kg`
`=5cm=0.05m`
`k=100N/m`
When the body leaves the spring let the velocity be v.
`1/2mv^2=1/2kx^2`
`rarr v=xsqrt(k/m)`
`=(0.05)xxsqrt((100)/(0.1))`
` =1.58 m/sec for the projectile moton
`theta=0^0,y=-2`
Now, `y=(u.sintheta)t-1/2gt^2`
`-2=(-1/2)xx(9.8)xxt^2`
`rarr t=0.63 sec`
`So, x=(ucostheta)t` ltbr. `=(1.58)xx(0.63)=1m`
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Knowledge Check

  • A block of 200 g mass is dropped from a height of 2 m on to a spring and compress the spring to a distance of 50 cm. The force constant of the spring is

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