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A body of mass m is travelling with a ve...

A body of mass m is travelling with a velocity vu. When a constant retarding force F is applied, it comes to rest after travelling a distance `s_(1)`. If the initial velocity is 2u with the same force F, the distance travelled before it comes to rest is `s_(2)`. then,

A

`s_(2)=4s_(1)`

B

`2s_(2)=2s_(1)`

C

`s_(2)=(s_(1))/(2)`

D

`s_(2)=s_(1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of the body under the influence of a constant retarding force. We will use the kinematic equations of motion to find the relationship between the distances \( s_1 \) and \( s_2 \). ### Step-by-Step Solution: 1. **Identify the Variables:** - Mass of the body: \( m \) - Initial velocity in the first case: \( v_1 = u \) - Initial velocity in the second case: \( v_2 = 2u \) - Retarding force: \( F \) - Distance travelled in the first case: \( s_1 \) - Distance travelled in the second case: \( s_2 \) - Final velocity in both cases: \( v = 0 \) 2. **Apply the Kinematic Equation for the First Case:** We can use the equation: \[ v^2 = u^2 + 2as \] For the first case: - Final velocity \( v = 0 \) - Initial velocity \( u = u \) - Distance \( s = s_1 \) - Acceleration \( a = -\frac{F}{m} \) (negative because it's a retarding force) Plugging these into the equation: \[ 0 = u^2 + 2\left(-\frac{F}{m}\right)s_1 \] Rearranging gives: \[ u^2 = \frac{2F}{m}s_1 \quad \text{(1)} \] 3. **Apply the Kinematic Equation for the Second Case:** For the second case: - Final velocity \( v = 0 \) - Initial velocity \( u = 2u \) - Distance \( s = s_2 \) - Acceleration \( a = -\frac{F}{m} \) Using the same kinematic equation: \[ 0 = (2u)^2 + 2\left(-\frac{F}{m}\right)s_2 \] Rearranging gives: \[ 4u^2 = \frac{2F}{m}s_2 \quad \text{(2)} \] 4. **Relate the Two Equations:** From equation (1): \[ s_1 = \frac{mu^2}{2F} \quad \text{(3)} \] From equation (2): \[ s_2 = \frac{4mu^2}{2F} = \frac{2mu^2}{F} \quad \text{(4)} \] 5. **Find the Relationship Between \( s_1 \) and \( s_2 \):** Now, substituting equation (3) into equation (4): \[ s_2 = 4s_1 \] ### Final Result: Thus, the relationship between \( s_1 \) and \( s_2 \) is: \[ s_2 = 4s_1 \]

To solve the problem, we need to analyze the motion of the body under the influence of a constant retarding force. We will use the kinematic equations of motion to find the relationship between the distances \( s_1 \) and \( s_2 \). ### Step-by-Step Solution: 1. **Identify the Variables:** - Mass of the body: \( m \) - Initial velocity in the first case: \( v_1 = u \) - Initial velocity in the second case: \( v_2 = 2u \) ...
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Knowledge Check

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