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The charge required to deposit 40.5 ...

The charge required to deposit 40.5 g of Al (atomic mass 27 g ) from fused ` Al _ 2 ( SO _ 4 ) _ 3 ` is

A

`4 34xx10^(5)C`

B

`43 4 xx10^(5)C`

C

`044xx10^(5)C`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

Gram equivalents of AI
` = (40.5)/(9 ) = 4.5 `
` because ` To deposit 1 g equivalent
1 Faraday or 96500 C electricity is required.
So, the charge required
` = 4.5 xx 96500 C = 4.34 xx 10 ^ 5 C `
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