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The position of a point in time t is giv...

The position of a point in time t is given by `x=a+bt-ct^(2),y=at+bt^(2)`. Its acceleration at time t is

A

b-c

B

b+c

C

2b-2c

D

`2sqrt(b^(2)+C^(2))`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • A point moves such that its displacement as a function of times is given by x^(2)=t^(2)+1 . Its acceleration at time t is

    A
    `(1)/(x^3)`
    B
    `-(1)/(x^(2))`
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    A
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    C
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    D
    zero

  • The position x of a particle with time, (t) as x=at^(2)-bt^(3) . The acceleration will be zero at time t equal to

    A
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