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With a neat labeeled diagram, prove that...

With a neat labeeled diagram, prove that if the angle of incidence and angle of emergence of a light ray falling on a glass slab are I and e respectively, then i=e.

Text Solution

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In the following figure, SR||PQ and NM is the refracted ray. Hence, `r=i_(1)." Now "_(g)n_(a)= sin i// sin r and ""_(a)n_(g)= sin i_(1)// sin e`

Also `""_(g)n_(a)=(1)/(""_(a)n_(g))`
`therefore (sin i)/(sin r)=(sin e)/(sin i_(1))`
As `r=i_(1),` it follows that sin i= sin e
`therefore i=e`.
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If the angle of incidence and angle of emergence of a light ray falling on a glass slab are I and e respectively, prove that,i=e.

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Knowledge Check

  • The angle between the incident and the emergent ray from a glass slab is

    A
    `90^(@)`
    B
    `0^(@)`
    C
    less than `90^(@)`
    D
    more than `90^(@)`

  • In the experiment on tracing the path of a ray of light passing through a rectangular glass slab, the correct setting of the protractor (D), for measuring the angle of incidence ( angle I ), and the angle of emergence ( angle e ) correspond, respectively, to diagrams :

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    K and M
    B
    K and N
    C
    L and M
    D
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  • A student does the experiment on tracing the path of a ray of light passing through a rectangular glass slab for different angles of incidence. He can get a correct measure of the angle of incidence and the angle of emergence by following the labelling indicated in figure :

    A
    A
    B
    B
    C
    C
    D
    D

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