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A resistance of 20 Omega is connected to...

A resistance of `20 Omega` is connected to a source of alternating current rated `110 V, 50 Hz`. Find (a) the `rms` current, (b) the maxium instantaneous current in the resistor and © the time taken by the current to change from its maximum value to the rms value.

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To solve the problem step by step, we will find the RMS current, the maximum instantaneous current, and the time taken for the current to change from its maximum value to the RMS value. ### Given: - Resistance (R) = 20 Ω - Voltage (V_rms) = 110 V - Frequency (f) = 50 Hz ### Step 1: Calculate the RMS Current (I_rms) ...
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A resistance fo 40 Omega is connected to an a.c. source of 220 V, 50 Hz. Find (i) the rms current (ii) maximum instantaneous current in the resistor (iii) time taken by the current to change from max. value to rms value

Rms value of an alternating current .

Knowledge Check

  • The rms value of an alternating current

    A
    is equal to 0.707 times peak value
    B
    is equal to 0.636 times peak value
    C
    is equal sqrt2 times the peak value
    D
    none of the above

  • A resistance of 25 Omega is connected to 100 V, 50 Hz a.c. source. What is the maximum instanteous current in the resistor?

    A
    6.66 A
    B
    `2sqrt(2)A`
    C
    `4sqrt(2)A`
    D
    `4/(sqrt(2))A`

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