The `K_alpha` and `K_beta` X-rays of molybdenum have wavelengths `0*71 A` and` 0*63 A` respectively. Find the wavelength of `L_alpha` X-ray of molybdenum.

Explanation

Since `K_alpha=E_K-E_L……(1) `
` lambdaK_alpha=0.71Å `
` lambdaK_beta=0.63Å `
` K_beta=E_K-E_M…….(2) `
` L_alpha=E_L-E_M…..(3) `
Subtracting (2) from (1) `K_alpha=K_beta=E_M-E_L=-L_alpha `
` L_alpha=K_beta-K_alpha `
` (3xx10^8)/(0.63xx10^-10)-(3xx10^8)/(0.71xx10^-10) `
` 4.761xx10^18-4.225xx10^18 `
` =0.526xx10^18 Hz `
Again `lambda=(3xx10^8)/(0.526xx10^-18)`
` =5.6xx10^-10=5.6Å`