Prove that a diagonal of a parallelogram divides it into two congruent triangles.
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opposites sides of parallelogram are parallel. Thus
So, `AB||DC` and `AD||BC`.
In `/_\ABC` and `/_\ADC`,
`/_BAC=/_DCA`
`AC=AC` (common)
`/_DAC=/_BCA`
Thus, with ASA congruency, `/_\ABC` and `/_\ADC` are congruent.
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