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Work Done In Isothermal Reversible Process

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Work Done In Isothermal Processes

Knowledge Check

  • Work done during isothermal reversible process is given

    A
    `w = (RT)/(n) ln (V_(f))/(V_(i))`
    B
    `w = - (nRT)/(n) ln (V_(f))/(V_(i))`
    C
    `w = - nRT ln (V_(f))/(V_(i))`
    D
    `w = - nRT ln (V_(f))/(V_(i))`
  • Calculate work done during isothermal reversible process when 5 mol ideal gas is expanded so that its volume is doubled at 400K .

    A
    `-11.5 kJ`
    B
    `- 344 kJ`
    C
    0
    D
    `-2.8 kJ`
  • Assertion : For an isothermal reversible process Q = - w i.e., work done by the system equals the heat absorbed by the system. Reason : Enthalpy change (DeltaH) is zero for isothermal process.

    A
    If both assertion and reason are true and the reason is the correct explanation of the assertion.
    B
    If both assertion and reason are true but reason is not the correct explanation of the assertion
    C
    If assertion is true but reason is false
    D
    If the assertion and reason both are false.
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