Home
Class 12
MATHS
For the curve y=x e^x , the point...

For the curve `y=x e^x` , the point

A

x=-1 is a point of minimum

B

x=0 is a point of minimum

C

x=-1 is a point of maximum

D

x=0 is a point of maximum

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MAXIMA AND MINIMA

    OBJECTIVE RD SHARMA|Exercise Chapter Test|30 Videos

  • MAXIMA AND MINIMA

    OBJECTIVE RD SHARMA|Exercise Section II - Assertion Reason Type|7 Videos

  • MATHEMATICAL REASONING

    OBJECTIVE RD SHARMA|Exercise Chapter Test|20 Videos

  • MEASURES OF CENTRAL TENDENCY

    OBJECTIVE RD SHARMA|Exercise Chapter Test|21 Videos

Similar Questions

Explore conceptually related problems

The tangent to the curve y = e^(2x) at the point (0, 1) meets the x-axis at

The tangent to the curve y = e^(2x) at the point (0, 1) meets the x axis at

Knowledge Check

  • For the curve y = xe^(x) , the point

    A
    x = -1 is a point of minima
    B
    x = 0 is a point of minima
    C
    x= -1 is a point of maxima
    D
    x=0 is a point of maxima

  • For the curve y = xe^(x) , the point

    A
    x = -1 is a point of minimum
    B
    x = 0 is a minimum
    C
    x = -1 is a maximum
    D
    x = 0 is a maximum

  • The equation of the tangent to the curve y=e^(-|x|) at the point where the curve cuts the line x = 1, is

    A
    `x+y=e`
    B
    `e(x+y)=1`
    C
    `y+ex=1`
    D
    none of these

    • Similar Questions

    Explore conceptually related problems

    The tangent to the curve y = e^(2x) at the point (0,1) meets x - axis at :

    Where does the tangent to the curve y=e^(x) at the point (0,1) meet x-axis?

    The tangent to the curve y=e^(2x) at the point (0,1) meets X-axis at

    The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

    The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is

    Home
    Profile