The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision is

Options

A. `(kL^(2))/(2 M)`
B. `sqrt(Mk) L(c )`S
C. `(ML^(2))/(k)`
D. zero

Answer

B

Explanation

(b) `(1)/(2) M nu^(2) = (1)/(2) k L6(2) rArr nu = sqrt(k)/(M) . L`
Momentum `= M xx nu = M xx sqrt (k)/(M). L = sqrt(kM) . L`