A travelling wave has the frequency `v` and the particle displacement amplitude `A`. For the wave the particle velocity amplitude is ………………… and the particle acceleration amplitude is ……………………..

Answer

A, B

Explanation

Since `y = A sin (omegat - kx)`
`Displacement amplitude = A` (Max displacement)
Particle velocity, `v = (dy)/(dt) = A omega cos (omegat - kx)`
:. Velocity amplitude `= Aomega = 2pivA`
Particle acceleration
Acc = (dv)/(dt) = -Aomega^(2) sin (omegat - kx)`
:. Acceleration (Max acc) amplitude = Aomega^(2) = 4pi^(2)v^(2)A`