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Electrons in hydrogen like atom (Z= 3) m...

Electrons in hydrogen like atom `(Z= 3)` make transtion from the fifth is the fourth orbit and from the third orbit The resulting madition are incided nurmally an a meal plate and eject photoelectron the stopping potential for the photoelectron ejected by the longer wavelength
(Rydhery constant` = 1.094 xx10^(7) m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B, D

for hydrogen like atom energy of the nth orbit is
`E_(n) = (13.6)/(n^(2))Z^(2) eV atoms`
for transition from `n = 5 to n = 4`
`h nu = 13.6 xx 9 [(1)/(16) - (1)/(25)] = (13.6 xx 9 xx 9)/(16 xx 25) = 2.754 eV`
for transition from `n = 4 to n = 3 `,
`hv' = 13.6 xx 9 [(1)/(9)- (1)/(16)] = (13.6 xx 9 xx 7)/(9 xx 16) = 5.95 eV` for transition `n = 4 to n = 3 ,` the frequency is high and lence wavelength is short
for photoelectrnic effect , `hv' - W = eV_(0)` where `W= work`
function
`5.95 xx 1.6 xx 10^(-19) = 2 eV`
Again appling `hv - W= eV_(0)`
we get `2.754 xx 1.6 xx 10^(-19) - 2 xx 1.6 xx 10^(-19) = 1.6 xx 10^(-19)= V_(0)`
`rArr V_(0) = 0.754eV`
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Knowledge Check

  • Electrons in a sample of gas containing hydrogen-like atom (Z = 3) are in fourth excited state. When photons emitted only due to transition from third excited state to second excited state are incident on a metal plate photoelectorns are ejected. The stopping potential for these photoelectorns is 3.95 eV . now, if only photons emitted due to transition from fourth excited state to third excited state are incident on the same metal plate, the stopping potential for the emitted photoelectrons will be appoximetely equal to

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    B
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    C
    `0.65 eV`
    D
    None of these
  • If electron in a hydrogen atom has moves from n = 1 to n = 10 orbit, the potential energy of the system has

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    B
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    D
    become zero
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