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In cyclotron, magnetic field of 1.4 Wb//...

In cyclotron, magnetic field of 1.4 `Wb//m^(2)` is used. To accelerate protons, how rapidly should the electric field between the Dees be reversed?
` (pi=3.142, Mp = 1.67xx10^(-27) kg, 3=1.6xx10^(-19)C)`

Text Solution

Verified by Experts

Given : `B=1.4Wb m^(-2), m_(p)=1.67xx10^(-27)kg,`
`q_(p)=1.6xx10^(-19)C`
The time required to reverse semicircle is given by,
`t=(pi m_(p))/(Bq_(p))`
Substituting the values, we get
`t=(3.142xx1.67xx10^(-27))/(1.4xx1.6xx10^(-19))`
`=2.342 xx 10^(-8)s`
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Knowledge Check

  • A cyclotron in which flux density is 1.4 T is employed to accelerate protons. How rapidly should the field between the dees be reversed if mass of protoon be taken as 1.6 xx 10^(-27) kg ?

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    `(49)/(22) xx 10^(6)` Hz
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    A
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    `1xx10^(-5)V//m`
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    A
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