In cyclotron, magnetic field of 1.4 `Wb//m^(2)` is used. To accelerate protons, how rapidly should the electric field between the Dees be reversed?
` (pi=3.142, Mp = 1.67xx10^(-27) kg, 3=1.6xx10^(-19)C)`

Explanation

Given : `B=1.4Wb m^(-2), m_(p)=1.67xx10^(-27)kg,`
`q_(p)=1.6xx10^(-19)C`
The time required to reverse semicircle is given by,
`t=(pi m_(p))/(Bq_(p))`
Substituting the values, we get
`t=(3.142xx1.67xx10^(-27))/(1.4xx1.6xx10^(-19))`
`=2.342 xx 10^(-8)s`