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In Young's experiment interference bands...

In Young's experiment interference bands were produced on a screen placed at 150 cm from two slits, `0.015` mm apart and illuminated by the light of wavelength `6500Å` . Calculate the fringe width.

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Given ` D=150 cm 150xx10^(2-) m , d=0.15 mm =0.15xx10^(-3)m, lambda =6500 Å6500xx10^(-10)m, beta=?`
`:. Beta =(lambdaD)/(d)`
`:. Beta =(6500xx10^(-10)xx150xx10^(-2))/(0.15xx10^(-3))`
`beta =(65xx15)/(15)xx10^(-12)xx10^(5)xx10^(3)`
`beta =65xx10^(7+3)`
`beta =65xx10^(-4),`
`beta=6.5xx10^(-3)m`
`beta =6.5m`
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