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The percentage labelling (mixture of H(2...

The percentage labelling (mixture of `H_(2)SO_(4)` and `SO_(3))` refers to the total mass of pure `H_(2)SO_(4)`. The total amount of `H_(2)SO_(4)` found after adding calculated amount of water to `100 g` oleum is the percentage labelling of oleum. The higher the percentage lebeling of oleum higher is the amount of free `SO_(3)` in the oleum sample.
`100 g` sample of '149%' oleum was taken and calculated amount of `H_(2)O` was added to make `H_(2)SO_(4)`.`500 mL` solution of `x MKOH` solution is required to neutralize the solution. The value of `x` is.

A

`1 M`

B

`2 M`

C

`4 M`

D

`6 M`

Text Solution

Verified by Experts

The correct Answer is:
D

147% oleum sample implies `100 g` oleum sample on addition of `47 g` of `H_(2) O` will form `147 g H_(2) SO_(4)`.
Equivalent of `H_(2) SO_(4) = (147)/(49) = 3 = 3 xx 10^(3) mEq`
`:. mEq "of" H_(2)SO_(4) =` mEq of `NaOH`
`3 xx 10^(3) = 500 mL xx x xx 1`
`x = (3000)/(500) = 6 M`
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Knowledge Check

  • The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) . The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum. The higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. What is the amount of free SO_(3) in an oleum sample labelled as '118%'.

    A
    0.4
    B
    0.5
    C
    0.7
    D
    0.8
  • The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) . The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum. The higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. The percent free SO_(3) is an oleum is 20%. Label the sample of oleum in terms of percent H_(2) SO_(4) .

    A
    1.135
    B
    1.045
    C
    1.0675
    D
    1.2
  • A sample of oleum is labelled 109% . The % of free SO_(3) in the sample is

    A
    `40%`
    B
    `80%`
    C
    `60%`
    D
    `9%`
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