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The density of 1 M solution of NaCl is 1...

The density of `1 M` solution of `NaCl` is `1.0585 g mL^(-1)`. The molality of the solution is

A

1.0585

B

`1.00`

C

`0.10`

D

0.0585

Text Solution

Verified by Experts

The correct Answer is:
B
Use formula
`d = M ((Mw_(2))/(1000) + (1)/(m)) implies 1.0585 = 1 ((58.5)/(1000) + (1)/(m))`
Solve for `m`:
`:.m = 1`
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Knowledge Check

  • The density of 3 M solution of NaCl is 1.25 "g L"^(-1) . The molality of the solution is :

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