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How may moles of electrons weigh one kil...

How may moles of electrons weigh one kilogram?

A

`6.023 xx ^(23)`

B

`(1)/(9.108) xx 10^(31)`

C

`(6.023)/(9.108) xx 10^(54)`

D

`(1)/(9.108 xx 6.023) xx 10^(8)`

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The correct Answer is:
To find how many moles of electrons weigh one kilogram, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the mass of one electron**: The mass of one electron is given as: \[ \text{Mass of one electron} = 9.108 \times 10^{-31} \text{ kg} \] 2. **Determine the number of electrons in one mole**: According to Avogadro's number, the number of particles (in this case, electrons) in one mole is: \[ N_A = 6.022 \times 10^{23} \text{ electrons/mole} \] 3. **Calculate the mass of one mole of electrons**: To find the mass of one mole of electrons, we multiply the mass of one electron by the number of electrons in one mole: \[ \text{Mass of one mole of electrons} = \text{Mass of one electron} \times N_A \] \[ \text{Mass of one mole of electrons} = (9.108 \times 10^{-31} \text{ kg}) \times (6.022 \times 10^{23} \text{ electrons/mole}) \] \[ \text{Mass of one mole of electrons} \approx 5.4858 \times 10^{-7} \text{ kg} \] 4. **Calculate the number of moles of electrons in 1 kg**: To find the number of moles of electrons in 1 kg, we divide 1 kg by the mass of one mole of electrons: \[ \text{Number of moles of electrons} = \frac{1 \text{ kg}}{\text{Mass of one mole of electrons}} \] \[ \text{Number of moles of electrons} = \frac{1 \text{ kg}}{5.4858 \times 10^{-7} \text{ kg/mole}} \approx 1.82 \times 10^{6} \text{ moles} \] ### Final Answer: Approximately \( 1.82 \times 10^{6} \) moles of electrons weigh one kilogram.

To find how many moles of electrons weigh one kilogram, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the mass of one electron**: The mass of one electron is given as: \[ \text{Mass of one electron} = 9.108 \times 10^{-31} \text{ kg} ...
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How many moles of electrons weigh one kilogram? (Mass of electron =9.108xx10^(-31) kg, Avogadro's number =6.023xx10^(23) )

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