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In a vernier callipers, N divisions of t...

In a vernier callipers, `N` divisions of the main scale coincide with `N + m` divisions of the vernier scale. what is the value of `m` for which the instrument has minimum least count.

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To solve the problem, we need to determine the value of \( m \) for which the least count of the vernier calipers is minimized. Here’s the step-by-step solution: ### Step 1: Understand the relationship between the main scale and the vernier scale We are given that \( N \) divisions of the main scale coincide with \( N + m \) divisions of the vernier scale. This can be expressed as: \[ N \text{ MS divisions} = (N + m) \text{ VS divisions} \] ### Step 2: Determine the value of one vernier scale division From the above relationship, we can find the value of one vernier scale division (VSD): \[ 1 \text{ VSD} = \frac{N}{N + m} \text{ MS divisions} \] ### Step 3: Define the least count of the vernier calipers The least count (LC) of the vernier calipers is defined as: \[ \text{LC} = 1 \text{ MS division} - 1 \text{ VSD} \] Substituting the value of VSD from Step 2, we get: \[ \text{LC} = 1 - \frac{N}{N + m} \] ### Step 4: Simplify the least count expression Now, we simplify the expression for the least count: \[ \text{LC} = 1 - \frac{N}{N + m} = \frac{(N + m) - N}{N + m} = \frac{m}{N + m} \] ### Step 5: Minimize the least count To minimize the least count, we need to maximize the fraction \( \frac{m}{N + m} \). Since \( N \) is constant, we can analyze the behavior of this fraction as \( m \) changes. ### Step 6: Analyze the function The fraction \( \frac{m}{N + m} \) increases as \( m \) increases. However, if \( m = 0 \), the least count becomes zero, which is not acceptable. Therefore, we need to find the smallest positive integer value of \( m \) that gives a finite least count. ### Step 7: Find the optimal value of \( m \) The smallest positive integer value for \( m \) is \( 1 \). Thus, substituting \( m = 1 \) into our least count expression: \[ \text{LC} = \frac{1}{N + 1} \] This gives us the minimum least count for the vernier calipers. ### Final Answer The value of \( m \) for which the instrument has the minimum least count is: \[ \boxed{1} \]

To solve the problem, we need to determine the value of \( m \) for which the least count of the vernier calipers is minimized. Here’s the step-by-step solution: ### Step 1: Understand the relationship between the main scale and the vernier scale We are given that \( N \) divisions of the main scale coincide with \( N + m \) divisions of the vernier scale. This can be expressed as: \[ N \text{ MS divisions} = (N + m) \text{ VS divisions} \] ...
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Knowledge Check

  • In a vernier caliper, 9 divisions of main scale match with 9+n divisions of vernier scale. What should be the value of n so that count of the instrument remains at minimum possible value?

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    C
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    D
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