The equation of a state of a gas is given by `p(V-b)=nRT`. If 1 mole of a gas is isothermally expanded from volume V and 2V, the work done during the process is

Options

A. (a) `RT ln|(2V-b)/(V-b)|`
B. (b) `RT ln|(V-b)/(V)|`
C. (c) `RT In|(V-b)/(2V-b)|`
D. (d) `RT In|(V)/(V-b)|`

Answer

A

Explanation

`W=int_V^(2V)pdV`
`=int_V^(2V)((nRT)/(V-b))dV`
`=nRT In((2V-b)/(V-b))`
Put `n=1`,
`:.` `W=RT In((2V-b)/(V-b))`