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The internal energy of a gas is given by...

The internal energy of a gas is given by `U=2pV`. It expands from `V_0` to `2V_0` against a constant pressure `p_0`. The heat absorbed by the gas in the process is

A

(a) `2p_0V_0`

B

(b) `4p_0V_0`

C

(c) `3p_0V_0`

D

(d) `p_0V_0`

Text Solution

Verified by Experts

The correct Answer is:
C
`W=pDeltaV=p_0(2V_0-V_0)=p_0V_0`
`DeltaU=U_f-U_i`
`=2p_0(2V_0)-2p_0V_0`
`=2p_0V_0`
`:.` `Q=W+DeltaU=3p_0V_0`
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