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The internal energy of a gas is given by...

The internal energy of a gas is given by `U=2pV`. It expands from `V_0` to `2V_0` against a constant pressure `p_0`. The heat absorbed by the gas in the process is

A

(a) `2p_0V_0`

B

(b) `4p_0V_0`

C

(c) `3p_0V_0`

D

(d) `p_0V_0`

Text Solution

Verified by Experts

The correct Answer is:
C
`W=pDeltaV=p_0(2V_0-V_0)=p_0V_0`
`DeltaU=U_f-U_i`
`=2p_0(2V_0)-2p_0V_0`
`=2p_0V_0`
`:.` `Q=W+DeltaU=3p_0V_0`
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Knowledge Check

  • The internal energy of a gas is given by U = 3 pV. It expands from V_(0) to 2V_(0) against a constant pressure p_(0) . The heat absorbed by the gas in the process is

    A
    `p_(0)V_(0)`
    B
    `2p_(0)V_(0)`
    C
    `3p_(0)V_(0)`
    D
    `4p_(0)V_(0)`

  • The internal energy of a gas is given by U= 5 + 2PV . It expands from V_(0) to 2V_(0) against a constant pressure P_(0) . The heat absorbed by the gas in the process is :-

    A
    `-3P_(0)V_(0)`
    B
    `3P_(0)V_(0)`
    C
    `2P_(0)V_(0)`
    D
    `P_(0)V_(0)`

  • The internal energy of a gas is given by U = 3 pV. It expands from V_(0) to 2V_(0) against a constant pressure p_(0) . What is the value of gamma(=C_(P)//C_(V)) for the given gas?

    A
    `1.33`
    B
    `1.4`
    C
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    D
    None of these

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