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Find the ionisation energy of a doubly ...

Find the ionisation energy of a doubly lonized lithium atom.

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The correct Answer is:
A, B, D
`Z = 3 for doubly ionized atom E prop Z^2`
lonization energy of hydrogen atoms is 13.6 eV.
`:.` lonisation energy of this atom
`(3)^2(13.6)
=122.4 eV
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Knowledge Check

  • For a doubly ionised Li-atom

    A
    Angular momentum of an electron in `3rd` orbit is `(3h)/(2pi)`
    B
    energy of electron in `2nd` ecited state is `-13.6 eV`.
    C
    Speed of electron in `3rd` orbit is `(c)/(137)`, where c is speed of light
    D
    Kinetic energy of electron is 2nd excited state is half of the magnitude of the potential energy.

  • The wavelength of the first line of the Balmer series of hydrogen atom is lamda . The wavelength of the corresponding line line of doubly ionized lithium atom is

    A
    `(lamda)/(3)`
    B
    `(lamda)/(4)`
    C
    `(lamda)/(9)`
    D
    `(lamda)/(27)`

  • The ionisation energy of 10 times innised sodium atom is

    A
    `13.6 eV`
    B
    `13.6 xx 11eV`
    C
    `(13.6)/(11)eV`
    D
    `13.6 xx (11)^(2)eV`

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    In a hydrogen atom if electron is replaced by a muon then find the ionisation energy of atom. (Given mass of mu = 207 m_e )

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