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Find the energy and mometum of a photon...

Find the energy and mometum of a photon of ultraviolet radiation of 280 nm wavelength.

Text Solution

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The correct Answer is:
A, B, D
`E = (hc)/(lambda) , P =(h)/(lambda)
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Knowledge Check

  • The energy of a photon of radiation having wavelength 300 nm is,

    A
    `6.63xx10^(29)J`
    B
    `6.63xx10^(-19)J`
    C
    `6.63xx10^(-28)J`
    D
    `6.63xx10^(-17)J`

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