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A doubly ionized lithium atom is hydroge...

A doubly ionized lithium atom is hydrogen like with atomic number 3. Find the wavelength of the radiation required to excite the electron in `Li^(++)` from to the third Bohr orbit (ionization energy of the hydrogen atom equals 13.6 eV).

Text Solution

Verified by Experts

The correct Answer is:
A, C, D

In hydrogen atom,
`Delta E_1 = E_3 - E_1 = 12.1 eV`
`E prop Z^2`
`:. For Z = 3,`
`DeltaE_2 = ((3))^2 DeltaE_1 = ((3))^2 ((12.1))`
=108.9 Å
`:. Lambda = (12375)/(108.9) ~~ 113 Å.`
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Knowledge Check

  • A doubly ionized lithim atom is hydrogen like with atomic number 3. Find the wavelength of the radiation required to excite the electron in Li^(2+) from the first to the third Bohr orbit. The ionization energy of the hydrogen atom is 13.6 eV. (Take hc=1240 eV nm)

    A
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    B
    10.7 nm
    C
    12.7 nm
    D
    13.4 nm
  • A double charged lithium atom is equivalent to hydrogen whose atomic numer is 3 . The wavelength of required radiation for emitted electron from first to third Bohr orbit in Li^(++ will be (lonisation energy of hydrogen atom is 13.6 eV )

    A
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    B
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    C
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    D
    `113.74 Å`
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    `3.4 eV`
    B
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    D
    `1.3 eV`
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