if we assume only gravitational attract...

if we assume only gravitational attraction between proton and electron in hydrogen atom and the Bohr quantizaton rule to be followed, then the expression for the ground state energy of the atom will be (the mass of proton is M and that of electron is m.)

increases 4 times

decreases 4 times

increases 8 times

decreases 8 times

Text Solution

Verified by Experts

The correct Answer is:

`(mv^2)/(r ) = (GMm)/(r^2)…..(i)`
`mvr =(h)/(2pi) (for n =1) ….(ii)`
Solving these two equations, we can find v and r.
Then,
`E = (1)/(2) mv^2 - (GMM)/(r )`

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If we assume only gravitational attraction between protect and electron in hydrogen atom and the Bohr's quantization rule kto be allowed , then the expression for the ground state energy of the atom will be (the mass of proton is M and that of electron is m )

`(G^(2)M^(2)m^(2))/(h^(2))`

`(2pi^(2)G^(2)M^(2)m^(3))/(h^(2))`

`(2pi^(2)GM^(2)m^(3))/(h^(2))`

`(h^(2))/(G^(2)M^(2)n^(2))`

Select the correct statement about the space between a proton and electron in hydrogen atom.

Full of air

Full of ether

Full of electromagnetic radiations

Empty

Energy of electron of hydrogen atom in second Bohr orbit is

`-5.44 xx 10^(-19) J`

`-5.44 xx 10^(-19) kJ`

`-5.44 xx 10^(-19) ` cal

`-5.44 xx 10^(-19) ` eV