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The pair in which both species have same...

The pair in which both species have same magnetic moment (spin only value) is .

A

`[Cr(H_(2)O)_(6)]^(2+)[ CoCI_(4)]^(2-)`

B

`[Cr(H_(2)O)_(6)]^(2+)[ Fe(H_(2)O)_(6)]^(2-)`

C

`[Mn(H_(2)O)_(6)]^(2+)[Cr(H_(2)O)_(6)]^(2-)`

D

`[CoCI_(4)]^(2-),[Fe(H_(2)O)_(6)]^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
b
Spin only magnetic moment` mu=sqrt(n(n +2))`
where n= number of unpaied electrons. Number of unpaied in `Cr^(2+)([Ar] 3d^(4))` is 4 in `Co^(2+) ([Ar]rd^(1))` is 3. in `Fe^(2+)([Ar]3d^(6)` is 4. in `Mn^(2+)([Ar]3d^(6))`is 5.
As the numbe of unpaired elctrons in `Cr^(2+) and Fe^(2+)` are same, hence, `[Cr(H_(2)O)_(6)]^(2+) and [Fe(H_(2)O)_(6)]^(2+)` will have same magnetic moment.
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Knowledge Check

  • The pair in which both species have the same magnetic moment (spin only value) is

    A
    `[Cr(H_2O)_6]^(2+) , [CoCl_4]^(2-)`
    B
    `[Cr(H_2O)_6]^(2+) , [Fe(H_2O)_6]^(2+)`
    C
    `[Mn(H_2O)_6]^(2+) , [Cr(H_2O)_6]^(2+)`
    D
    `[CoCl_4]^(2-) , [Fe(H_2O)_6]^(2+)`

  • The pair in which both species have same magnetic moment is -

    A
    `[Cr(H_(2)O)_(6)]^(2+), [CoCl_(4)]^(2-)`
    B
    `[Cr(H_(2)O)_(6)]^(2+), [Fe(H_(2)O)_(6)]^(2+)`
    C
    `[Mn(H_(2)O)_(6)]^(2+), [Cr(H_(2)O)_(6)]^(2+)`
    D
    `[CoCl_(4)]^(2-) , [Fe(H_(2)O)_(6)]^(2+)`

  • The pair in which both spacies have the same magnetic moment ( spin only) value is :

    A
    `[Cr(NH_(3))_(6)]^(3+),[Co[H_(2)O)_(6)]^(3)`
    B
    `[Cr(NH_(3))_(6)]^(3+),[Fe(H_(2)O)_(6)]^(2+)`
    C
    `[Co(NH_(3))_(6)]^(2+),[Cr(NH_(3))_(6)]^(3+)`
    D
    `[Mn(H_(2)O)_(6)]^(2+),[Fe(H_(2)O)_(6)]^(2+)`

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