Home
Class 12
PHYSICS
The potential difference that must be ap...

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface , having work function `5.01 eV` , when ultraviolet light of `200 nm` falls on it , must be

Doubtnut Promotions Banner Mobile Dark

Text Solution

Verified by Experts

The correct Answer is:
D

`k_(max) =(hc)/(lambda) - W = (hc)/(lambda) - 5 .0.1= (12375)/(lambda( "in" Å) ) - 5.01`
`= (12375)/( 2000) - 5.01 = 6.1875- 5.01 = 1.17775 ~= 1.2V`
|

Topper's Solved these Questions

  • AIIMS 2016

    AIIMS PREVIOUS YEAR PAPERS|Exercise PHYSICS|60 Videos
  • AIIMS 2018 PAPER 1

    AIIMS PREVIOUS YEAR PAPERS|Exercise PHYSICS|37 Videos

Similar Questions

Explore conceptually related problems

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength `2000A` falls on it. The potential difference applied to stop the fastes photoelectrons is `[h=4.14xx10^(-15)eVs]`

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be

What potential difference must be applied to stop the fastest photoelectrons emitted by a nickel surface under the action of ultraviolet light of wavelength `2000Å`? The work function of nickel is 5.01 eV.

The work function of the nickel is 5 eV. When a light of wavelength 2000 Å falls on it ,it emits photoelectrons in the circuit .Then, the potential difference necessary to stop the faster electrons emitted is (Given ,`h=6.67xx10^(-34)J-s)`

निकिल पृष्ठ जिसका कार्य-फलन 5.01 eV है, से निकलने वाले तीव्रतम फोटो इलेक्ट्रॉन (फोटॉन) को रोकने के लिये आवश्यक विभवान्तर, जब उस पर 200 nm का पराबैंगनी प्रकाश आपतित होता है, होगा

The work function of a metallic surface in 5.0/eV. Photoelectrons are emitted when light of `lamda=2000Å` falls-on it. The P.D. to stop fastest photoelectrons is :

200 nm का पराबैंगनी प्रकाश पड़ने पर 5.01 eVकार्य - फलन वाले निकल पृष्ठ द्वारा उत्सर्जित तेज फोटो - इलेक्ट्रोनो को रोकने के लिए जो विभवांतर लगाया जाना चाहिए , वह है

Ultraviolet light of 200 nm wavelength is incident on nickel surface having work function of 5.01 eV.Potential difference of ………
Volt should be applied to stop electron emitted with maximum speed.

What P.D. must be applied to stop the fastest photo electron emitted by a nickel surface when illuminated by ultraviolet light of wave length `2000^(@)A`. The work function of nickel is 5 eV

The work function of a metallic surface is 5.01 e V. The photoelectrons emitted when light of wavelength 2000 `A^@` falls on it . The potential difference applied to stop the fastest photo electrons is : `(h = 4.14 xx 10^(-15) e V)`

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface , having work function `5.01 eV` , when ultraviolet light of `200 nm` falls on it , must be

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000A falls on it. The potential difference applied to stop the fastest photoelectrons is

Work function of nickel is 5.01 eV. When ultraviolet radiation of wavelength 200 Å is incident on it, electrons are emitted. What will be the maximum velocity of emitted electrons?

The work function of a metallic surface is 5.01 eV. The photo-electrons are emitted when light of wavelength 2000 `Å` falls on it. The potential difference applied to stop the fastest photo-electrons is `[h=4.14xx10^-15 eVs]`