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In the diagram 100kg block is moving up ...

In the diagram `100kg` block is moving up with constant velocity, then find out the tension at point `P` :

Text Solution

Verified by Experts

The correct Answer is:
1470


`T=3F`
2F=mg
`2F=100xx9.8" "So, T=3F`
`F=900N " "T=3xx490`
`" "=1470N`
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Knowledge Check

  • In the block moves up with constant velocity v m//s. Find F

    A
    `F=(mg)/(2)`
    B
    `F=(2mg)/(3)`
    C
    `F=(mg)/(3)`
    D
    `F=(m)/(3)`
  • A 100 kg block is suspended with the help of three strings A, B and C. The tension in the string A is

    A
    50 g N
    B
    100 g N
    C
    20 g N
    D
    `100sqrt(2) g N`
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