Balance the following by ion electron method (basic medium):
`Cr(OH)_(3)+IO_(3)^( ө)rarrI^(ө)+CrO_(4)^(2-)`

Explanation

To balance the given redox reaction in basic medium using the ion-electron method (also known as the half-reaction method), follow these steps:

### Step 1: Identify Oxidation and Reduction
1. **Determine the oxidation states** of the elements in the reactants and products:
- For `Cr(OH)₃`:
- Cr: +3 (since OH is -1 and there are 3 OH groups, total -3)
- For `IO₃⁻`:
- I: +5 (O is -2, total -6 from 3 O, and the overall charge is -1)
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