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200 mL of hydrogen and 250 mL of nitroge...

200 mL of hydrogen and 250 mL of nitrogen, each measured at `15^(@)C` and 760 mm pressure of the mixtue at `15^(@)C` ?

Text Solution

Verified by Experts

As temperature is kept constant at `15^(@)C` for calculation of partial pressure of `H_(2)` gas
`P_(1)V_(1)=P_(2)V_(2)`
`implies200xx760=P_(2)xx500impliesp_(H_(2))=380mm`
Hence final pressure of the mixture is
`304+380=684mm`
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Knowledge Check

  • A mineral containing iron(II) sulphide but no other sulphides is treated with excess hydrochloride acid to produce hydrogen sulphide. . If a 3.15g sample of the mineral yields 448 mL of hydrogen sulphide gas (measured at 0^(@)C and 760 mm Hg), what is the mass percentage of iron (II) sulphide inthe sample?

    A
    20.4
    B
    35.5
    C
    55.8
    D
    71
  • 500 mL of nitrogen at 27^(@)C is cooled to -5^(@)C at the same pressure. The new volume becomes

    A
    326.32 mL
    B
    446.66 mL
    C
    546.32 mL
    D
    771.56 mL
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