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What is significance of T DeltaS in Delt...

What is significance of `T DeltaS` in `DeltaG = DeltaH - T DeltaS`?

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It is quantitative measure of the randomness of the system.
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…… = Delta H - T Delta S

Significance Of Delta

Knowledge Check

  • Delta G = Delta H -T Delta S was given by

    A
    Faraday
    B
    Kirchhoff
    C
    Einstein
    D
    Gibbs-Helmholtz

  • If Delta G = Delta H - T Delta S and Delta G = Delta H + T [ (d(Delta G))/(dT) ]_P then variation of EMF of cell , with temperature T, is given by

    A
    `(Delta S)/(nF)`
    B
    `-(Delta S)/(nF)`
    C
    `(DeltaH)/(nF)`
    D
    `(Delta G)/(nF)`

  • For which of the following DeltaE = DeltaH

    A
    `N_(2)O_(4)(g) iff 2NO_(2)(g)`
    B
    `2SO_(2)(g)+O_(2)(g)iff2SO_(3)(g)`
    C
    `H_(2)(g)+Cl_(2)(g)iff2HCl(g)`
    D
    `H_(2)(g)+(1)/(2)O_(2)(g)iffH_(2)O(l)`

    • Similar Questions

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    Correct relation for isothermal reversible expansion of an ideal gas is DeltaS = 0 DeltaG = - T DeltaS DeltaH != 0 DeltaU != 0

    Gibbs-Helmoholtz equation relates the free energy change to the enthalpy and entropy changes of the process as (DeltaG)_(PT) = DeltaH - T DeltaS The magnitude of DeltaH does not change much with the change in temperature but the enrgy factor T DeltaS changes appreciably. Thus, spontaneity of a process depends very much on temperature. For the reaction at 298K, 2A +B rarr C Deltah = 100 kcal and DeltaS = 0.020 kcla K^(-1) . If DeltaH and DeltaS are assumed to be constant over the temperature range, at what temperature will the reaction become spontaneous?

    Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. For the spontaneity of a reaction, which statement is true?

    Work done by the system in isothermal reversible process is w_(rev.)= -2.303 nRT "log"(V_(2))/(V_(1)) . Also in case of adiabatic reversible process work done by the system is given by: w_(rev.) = (nR)/(gamma -1) [T_2 - T_1] . During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy DeltaS = q_(rev.)/T . The entropy changes also occurs during transformation of one state to other end expressed as DeltaS = DeltaH/T . Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and DeltaG=DeltaH - T DeltaS . The heat of vaporisation and heat of fusion of H_2O are 540 cal//g and 80 cal//g . This ratio of (DeltaS_(vap.))/(DeltaS_("fusion")) for water is:

    यदि Delta G = Delta H - T Delta S और Delta G = Delta H+T[ ( d ( Delta G))/( d T)] तब ताप T के साथ, सेल E के EMF में परिवर्तन, निम्न द्वारा दिया जाता है

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