Calculate the amount of carbon dioxide that could be produced when
a. `1` mol of carbon is burnt in air
b. `1` moles of carbon is brunt in `16 g` of dioxygen.
`2` moles of carbon are burnt in `16 g` of dioxygen.

Explanation

The balanced equation for the combustion of carbon in dioxygen`//`air is
`underset((32 g))(underset(1 mol)(C(s))underset(1 mol)(+)O_(2)(g))rarr underset((44 g))(underset(1 mol)(CO_(2)(g)))`
a. In air, combustion is complete. Therefore, `CO_(2)` produced from the combustion of `1 mol` of carbon `=44 g`.
b. As only `16 g` of dioxygen is avaliable, it can combine only with `0.5 mol` of carbon, i.e., dioxygen is the limiting reactant. Hence, `CO_(2)` produced `=22 g`.
c. Here again, dioxygen is the limiting reactant. `16 g` of dioxygen can combine only with `0.5 mol` of carbon. `CO_(2)` produced again is equal to `22 g`.