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(i) Calculate the number of electrons wh...

(i) Calculate the number of electrons which will together with one gram .
(ii) Calculate the mass and charge on one mole of electrons .

Text Solution

Verified by Experts

`9.11xx10^(-28) g` is the mass of `1` electron `1 g` is the mass of
`(1xx1)/(9.11xx10^(-28))=(10xx27)/(9.11)=1.099xx10^(27)`
b. Mass of `1` electron `=9.1xx10^(-31)kg`
Mass of `6.023xx10^(23)` electrons
`=6.023xx10^(23)xx9.1xx10^(-31) kg`
`=5.48xx10^(-7)kg`
Charge of one electron `=1.6xx10^(-19)` coulomb
Charge of `6.023xx10^(23)` electrons
`=6.023xx10^(23)xx1.6xx10^(-19)`
`=9.65xx10^(4)C`
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Knowledge Check

  • The number of electrons which will together weigh one gram is

    A
    `1.098xx10^(27)` electrons
    B
    `9.1096xx10^(31)` electrons
    C
    1 electron
    D
    `1xx10^(4)` electrons
  • The mass and charge of 1 mole electrons will be:

    A
    1kg,96500C
    B
    0.55mg: 96500C
    C
    1.55mg:96500C
    D
    5.5mg 96500C
  • The mass of one mole of electron is

    A
    `9.1 xx 10^(-28) g`
    B
    `0.55 mg`
    C
    `9.1 xx 10^(-24)g`
    D
    `1.008 mg`
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