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Calculate the mass of sodium acetate (CH...

Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar qqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.

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To calculate the mass of sodium acetate (CH₃COONa) required to make a 500 mL of 0.375 M aqueous solution, we can follow these steps: ### Step 1: Convert the volume from mL to L The volume of the solution is given as 500 mL. To convert this to liters, we use the conversion factor \(1 \text{ L} = 1000 \text{ mL}\). \[ \text{Volume in L} = \frac{500 \text{ mL}}{1000 \text{ mL/L}} = 0.5 \text{ L} \] ...
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Calcualte the mass of sodium acetate (CH_(3)COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol^(-1) .

How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?

Knowledge Check

  • Calculate the mass of sodium carbonate required to prepare 500 ml of a semi- normal solution

    A
    `13.25 g`
    B
    `26.5 g`
    C
    `53 g`
    D
    `6.125 g`
  • The amount of oxalic acid required to prepare 300 mL of 2.5 M solution is : (molar mass of oxalic acid = 90 g mol^(–1) ) :

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    D
    94.5 g
  • What mass of magnesium hydroxide is required to neutralise 125 mL of 0.136 M HCl solution ? ("Substance")/(Mg(OH)_(2)) " " ("Molar mass")/(58.33 " g mol"^(-1))

    A
    0.248 g
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