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The standard electrode potential for Den...

The standard electrode potential for Deniell cell is `1.1V`. Calculate the standart Gibbs energy for the reaction.
`Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq)+Cu(s)`

Text Solution

AI Generated Solution

To calculate the standard Gibbs energy (ΔG°) for the reaction given the standard electrode potential (E°) for the Daniell cell, we can follow these steps: ### Step 1: Identify the given values - Standard electrode potential (E°cell) = 1.1 V - The reaction is: \[ \text{Zn(s)} + \text{Cu}^{2+}(aq) \rightleftharpoons \text{Zn}^{2+}(aq) + \text{Cu(s)} \] ...
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The standard electrode potential for Daniell cell is 1.1 V. Calculate the standard Gibbs energy for the reaction. Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu(s)

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Knowledge Check

  • The standard electrode potential for Daniel cell is 1.1V . Calculate the standard Gibbs energy of the reaction (In KJ/mol) Zn_((s))+Cu_((aq))^(2+)rarrZn_((aq))^(2+)+Cu_((s))

    A
    `106.15`
    B
    `212.3`
    C
    `193`
    D
    `403`
  • The standard electrode potential for Daniel cell is 1.1V . Calculate the standard Gibbs energy of the reaction (In KJ/mol) Zn_((s))+Cu_((aq))^(2+)rarrZn_((aq))^(2+)+Cu_((s))

    A
    `106.15`
    B
    `212.3`
    C
    `193`
    D
    `403`
  • What is the Gibbs energy of the following reaction? Zn(s)+Cu^(2+) (aq) rarr Zn^(2+)(aq)+Cu^(2+) (s), E_("cell")^(@)=1.1 V

    A
    `106135.75 J mol^(-1)`
    B
    `21227 J mol^(-1)`
    C
    `-212.27 kJ mol^(-1)`
    D
    `21227 J mol^(-1)`
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    If the standed electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction Zn(s)+Cu^(2+)(aq) hArrZn^(2+)(aq)+Cu(s) at 300 K is approximately (R=8JK^(-1)mol^(-1),F=96000Cmol^(-1))

    Calculate standard Gibbs free energy for the reaction : Zn+Cu^(2+)toZn^(2+)+Cu,E_("cell")^(@)=1.10V

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    For a cell reaction, Zn+ Cu^(2+)(aq) to Zn^(2+)(aq)+ Cu Cell representation is