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For the oxidation of ferric oxalate to C...

For the oxidation of ferric oxalate to `CO_(2), 18F` of electricity is required. How mnay moles of ferric oxalate is oxidized ?

Text Solution

Verified by Experts

The correct Answer is:
3
Ferric oxalate `[Fe_(2)(C_(2)O_(4))_(3)rarr2Fe^(3+)+3C_(2)O_(4)^(2-)]`
`3C_(2)O_(4)^(2-)rarr 6CO_(2)+6e^(-) [Fe^(3+)` does not change `]`
`:. 6F=1 mol of Fe_(2)(C_(2)O_(4))_(3)`
`18F=3 mol of Fe_(2)(Fe_(2)(C_(2)O_(4))_(3)`
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Knowledge Check

  • Chemical formula of ferric oxide is:

    A
    FeO
    B
    `Fe_(2)O_(3)`
    C
    `Fe_(3)O_(4)`
    D
    none of these

  • The number of moles of KMnO_(4) that will be required to react with one mol of ferrous oxalate is

    A
    `3/5`
    B
    `2/5`
    C
    `4/5`
    D
    1

  • The numbe of mole of MnO_(4)^(-) required by 1 mole of ferric exalate for oxidation is/are-

    A
    0.2
    B
    1.2
    C
    2.6
    D
    5.2

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