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How may alpha- and beta- particles will ...

How may `alpha-` and `beta-` particles will be emitted when `._(90)Th^(232)` changes into `._(82)Pb^(208)`?

Text Solution

Verified by Experts

`._(90)Th^(232) rarr ._(82)Pb^(208) + x ._(2)He^(4) + y ._(-1)e^(0)`
Remembering that the total atomic number as well as mass number must be equal to the two sides of the equation, we have
`208 + 4x + 0y = 232`
i.e., `4x = 24`
and `82 + 2x - y = 90`
or `2x - y = 8`
Solving Eqs. (i) and (ii), we get `x = 6` and `y = 4`.
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Knowledge Check

  • The number of alpha- and beta- particles emitted when a radioactive element ._(90)E^(322) changes into ._(86)G^(220) will be

    A
    5 and 4
    B
    2 and 3
    C
    3 and 2
    D
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  • The number of alpha and beta particles emitted in the conversion of _(90) Th ^(232) to _(82) Pb ^(208) are

    A
    `6,4`
    B
    `4,6`
    C
    `8,6`
    D
    `6,8`
  • The number of alpha and beta -particles emitted during the transformation of ._(90)Th^(232) " to " ._(82)Pb^(208) are respectively

    A
    4, 2
    B
    2, 2
    C
    8, 6
    D
    6, 4
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