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In alpha- decay , n//p ratio :...

In `alpha-` decay , `n//p` ratio `:`

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._(15)P^(29) has n//p ratio too low for stability. Its stability can be increased by a. Positron emission b. Beta-decay c. Alpha-decay d. Electron capture

In beta- decay n//p ratio :

Statement: Neutron decay result in beta- emission and emission of neutrino. Explanation: Higher values of n//p ratio give rise to neutron decay.

During alpha decay of a nucleus, how does the neutron to proton ratio change?

In how many ways among the following given, a nuicleus with high n/p ratio is expected to decay alpha -decay, beta -decay, positron decay,K-electron capture.

Assertion : For maximum stability N/P ratio must be equal to 1 Reason : Loss of alpha - beta - particles has no role in N/P ratio

पॉजिट्रॉन क्षय के कारण n/p अनुपात

Discuss the alpha decay process with example.

During alpha -decay, n/p ratio :

प्रक्कथन : अधिकतम स्थायित्व के लिये N/P अनुपात 1 के बराबर होना चाहिये।
कारण : N/P अनुपात में `alpha` एवं `beta` कणों की हानि की कोई भूमिका नहीं होती है।

If `1,alpha,alpha^2,alpha^3,…,alpha^(n-1)` be the `n^(th)` roots of unity, then prove that `1^p+alpha^p+(alpha^2)^p+(alpha^3)^p+…+(alpha^(n-1))^p={{:(0,if" "pnekn),(n,if" "p=kn):}" where p,k"epsilonN`

In how many way among the following , a nucleus with high n/p ratio is expected to decay alpha - decay , beta - decay , positron decay , electron capture .

In nuclear decay process if n/p ratio increases then which decay process may have ocurred

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