Silver crystallizes in fcc lattic. If the edge length of the cell is `4.07 xx 10^(-8) cm` and density is `10.5 g cm^(-3)`. Calculate the atomic mass of silver.

Explanation

To calculate the atomic mass of silver given that it crystallizes in a face-centered cubic (FCC) lattice, we can follow these steps:

### Step 1: Write down the given data
- Edge length of the unit cell (a) = \(4.07 \times 10^{-8} \, \text{cm}\)
- Density (\(\rho\)) = \(10.5 \, \text{g/cm}^3\)
- For FCC lattice, the number of atoms per unit cell (Z) = 4

### Step 2: Calculate the volume of the unit cell
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