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When 100 ml of O2-O3 mixture was passed ...

When 100 ml of `O_2-O_3` mixture was passed through turpentine oil, there was reduction of volume by 20 ml. If 100 ml of such a mixture is heated, what will be the increase in the volume?

Text Solution

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`O_3` is absorbed in turpentine oil.
volume of `O_3=20ml`
volume of `O_2=(100-20)=80ml`
On heating `O_3` is converted to `O_2`
`{:(2mol,,3mol),(2ml,,3ml),(2ml,,3ml),(20ml,,30ml):}`
Increase in volume `=(30-20)=10ml`
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