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The difference in the oxidation numbers ...

The difference in the oxidation numbers of two types of sulphul atoms in `Na_(2)S_(4)O_(6)` is…..

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`S_(4)O_(6)^(2-):O^(ө)-underset(O)underset(||)overset(O)overset(||)Soverset(+5)-overset(0)S-overset(0)S-underset(O)underset(||)overset(O)overset(||)Soverset(+5)-O^(ө)`
So difference in oxidation numbers of two types of `S=(5-0)=5`
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The difference in the oxidation numbers of the two types of sulphur atoms in Na_(2)S_(4)O_(6) is: Oxidation number of sulphur atom involved in coordinate bond formation is (+5) and that of middle sulphur atom is zero. Hence the difference in oxidation number of two types of sulphur aton will be (+5).]

The difference in the oxidation states of the two types of sulphur atoms in Na_(2)S_(4)O_(6) is :

Knowledge Check

  • The difference of the different oxidation number of the two of sulphur atoms in Na_(2)S_(2)O_(6) is

    A
    `+5`
    B
    `0`
    C
    `+10`
    D
    `-10`