If the angle between the vectors `vec(a)` and `vec(b)` is an acute angle, then the diffrence `vec(a)-vec(b)` is

Options

A. The major diagonal of the parallelogram
B. The minor diagnol of the parallelogram
C. Any of the above
D. None of the above

Explanation

To solve the question regarding the difference of two vectors \(\vec{a}\) and \(\vec{b}\) when the angle between them is acute, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Vectors**:
- Let \(\vec{a}\) and \(\vec{b}\) be two vectors.
- The angle \(\theta\) between them is given to be acute, which means \(0^\circ < \theta < 90^\circ\).

2. **Visualizing the Vectors**:
- Draw the vectors \(\vec{a}\) and \(\vec{b}\) originating from the same point, forming an acute angle \(\theta\).

3. **Constructing the Parallelogram**:
- To find \(\vec{a} - \vec{b}\), we can visualize this by constructing a parallelogram where \(\vec{a}\) and \(\vec{b}\) are adjacent sides.
- The diagonal from the origin to the opposite corner represents \(\vec{a} + \vec{b}\), while the diagonal from the origin to the corner opposite to \(\vec{b}\) represents \(\vec{a} - \vec{b}\).

4. **Identifying the Diagonals**:
- In a parallelogram formed by two vectors, the diagonal that represents \(\vec{a} + \vec{b}\) is the major diagonal.
- The diagonal that represents \(\vec{a} - \vec{b}\) is the minor diagonal.

5. **Conclusion**:
- Since the angle between \(\vec{a}\) and \(\vec{b}\) is acute, the vector \(\vec{a} - \vec{b}\) will also point in a direction that is closer to \(\vec{a}\) than to the opposite direction of \(\vec{b}\).
- Therefore, the difference \(\vec{a} - \vec{b}\) is a vector that is less than \(\vec{a}\) in magnitude but still points in the direction towards \(\vec{a}\).

### Final Answer:
The difference \(\vec{a} - \vec{b}\) is the minor diagonal of the parallelogram formed by \(\vec{a}\) and \(\vec{b}\).