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A particle moves in a circle of radius 2...

A particle moves in a circle of radius `2 cm` at a speed given by `v = 4t`, where `v` is in `cm s^-1` and `t` is in seconds.
(a) Find the tangential acceleration at `t = 1 s`
(b) Find total acceleration at `t = 1 s`.

Text Solution

Verified by Experts

(a) Tangential acceleration,
`a_t = (d v)/(d t) = (d)/( d t) (4 t) = 4 cm s^-2`
`a_c = (v^2)/(R ) = ((4)^2)/(2) = 8 cm s^-2`
`:. a = sqrt(a_t^2 + a_C^2) = sqrt((4)^2 + (8)^2) = 4 sqrt(5) cm s^-2`.
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