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Find the reading of spring balance as sh...

Find the reading of spring balance as shown in fig. Assume that mass M in equilibrium. (All surfaces are smooth).

Text Solution

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From force diagram of wedge,
`N cos 53^(@)=kx_(0)` ..(i)
From force diagram of smaller block:
`N=mg cos 37^(@)`
`Kx_(0)=N cos 53^(@)`
`kx_(0)=mg cos 37^(@) cos 53^(@)`
`kx_(0)=2.5 xx 10 xx 0.8 xx 0.6 = 12 N`.
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Knowledge Check

  • Find the reading of spring balance as shown in figure-2.154. Assume that mass M is in equilibrium :

    A
    8 N
    B
    9 N
    C
    12 N
    D
    Zero
  • In the arrangement shown in figure wedge of mass M moves towards left with an acceleration a. All surfaces are smooth. The acceleration of mass m relative to wedge is

    A
    `a//2`
    B
    `(2Ma)/(m)`
    C
    `(2(M+m)a)/(m)`
    D
    `((M+m)a)/(m)`
  • Two masses m_(1) and m_(2) are suspeded togther by a massless spring of spring constnat k (Fig). When the masses are in equilibrium, m_(1) is removed. Frequency and amplitude of oscillation of m_(2) are

    A
    `omega =sqrt((K)/(m_(1))), A (m_(2)g)/(K)`
    B
    `omega =sqrt((K)/(m_(2))), A (m_(1)g)/(K)`
    C
    `omega =sqrt((K)/(m_(1))), A=(m_(1)g)/(K)`
    D
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