A block is moving on an inclined plane making an angle `45^@` with the horizontal and the coefficient of friction is `mu`. The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define `N=10mu`, then N is
Text Solution
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The correct Answer is:
5
Case 1 For pushing the block up `F_(1) = mg sin 45^(@) + mu mg cos 45^(@)` `F_(1) = (mg)/(sqrt(2))+(mu mg)/(sqrt(2))` Case II force required to justpervent the block froin sliding down `F_(1) = mg sin 45^(@)- mu mg cos 45^(@)` `F_(2) = (mg)/(sqrt(2)) - (mu mg)/(sqrt(2))`
A brick of mass 2kg begins to slide down on a plane inclined at an angle of 45^(@) with the horizontal. The force of friction will be
A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is
A block of mass m is lying on an inclined plane. The coefficient of friction between the plane and the block is mu . The force (F_(1)) required to move the block up the inclined plane will be:-
A block rests on an inclined plane that makes an angle with the horizontal, if the coefficient of sliding friction is 0.50 and that of static friction is 0.75, the time required to slide the block 4 m along the inclined plane is -
A block rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and inclined plane is 0.8. If the frictional force on the block is 10 N, the mass of the block is
The force F_(1) that is necessary to move a body up an inclined plane is double the force F_(2) that is necessary to just prevent it form sliding down, then:
A block rests on a rough inclined plane making an angle of 30^@ with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10N, the mass of the block (in kg) is
Knowledge Check
A brick of mass 2kg just begins to slide down on inclined plane at an angle of 45^(@) with the horizontal. The force of friction will be
A
`19.6 sin 45^(@)`
B
`19.6cos45^(@)`
C
`9.8sin 45^(@)`
D
`9.8cos 45^(@)`
A brick of mass 2kg begins to slide down on a plane inclined at an angle of 45^(@) with the horizontal. The force of friction will be
A
`19.6sin45^(@)`
B
`19.6cos45^(@)`
C
`9.8sin45^(@)`
D
`9.8cos45^(@)`
A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is
A
`mg cos theta`
B
`sqrt(mu^(2) + 1) mg cos theta`
C
`(mumg cos theta)/(sqrt(mu^(2) + 1))`
D
`mumg theta`
CENGAGE PHYSICS-NEWTON'S LAWS OF MOTION 2-Integer type
