A block is moving on an inclined plane m...

A block is moving on an inclined plane making an angle `45^@` with the horizontal and the coefficient of friction is `mu`. The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define `N=10mu`, then N is

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The correct Answer is:

Case 1 For pushing the block up

`F_(1) = mg sin 45^(@) + mu mg cos 45^(@)`
`F_(1) = (mg)/(sqrt(2))+(mu mg)/(sqrt(2))`

Case II force required to justpervent the block froin sliding down
`F_(1) = mg sin 45^(@)- mu mg cos 45^(@)`
`F_(2) = (mg)/(sqrt(2)) - (mu mg)/(sqrt(2))`

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