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The displacement x(in metres) of a parti...

The displacement x(in metres) of a particle performing simple harmonic motion is related to time t(in seconds) as `x=0.05cos(4pit+(pi)/4)` .the frequency of the motion will be

A

0.5 Hz

B

1.0 Hz

C

1.5 Hz

D

2.0 Hz

Text Solution

Verified by Experts

The correct Answer is:
D

Compare the given equation with the standard from
`y=a cos [(2pi t)/T-(2pi x)/lambda]`
Coefficient of `t=(2pi)/T=2 pi n=4 pi, n =2` Hz
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Knowledge Check

  • The phase (at a time t) of a particle in simple harmonic motion tells

    A
    only th position of the particle at time t
    B
    only the direction of motion of the particle at time t
    C
    both the position and direction of motion of the particle at time t
    D
    neither the position of the particle nor its direction of motion at time t
  • The total energy of a particle having a displacement x, executing simple harmonic motion is

    A
    `prop x`
    B
    `prop x^(2)`
    C
    independent of x
    D
    `prop x^(1//2)`
  • A particle executes simple harmonic motion and it is located at x=a, b and c at time t_(0), 2t_(0) and 3t_(0) respectively. The frequency of the oscillation is :

    A
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    C
    `(1)/(2pit_(0))cos^(-1)((a+b)/(2c))`
    D
    `(1)/(2pit_(0))cos^(-1)((2a+3c)/(b))`
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