`5.5mg` of nitrogen gas dissolves in 180g of water at 273 K and 1 atm pressure due to nitrogen gas. The mole fraction of nitrogen in 180g of water at 5 atm nitrogen pressure is approximately

Options

A. `1xx10^(-6)`
B. `1xx10^(-5)`
C. `1xx10^(-3)`
D. `1xx10^(-4)`

Answer

D

Explanation

Amount of nitrogen gas at 5 atm
`=5xx5.5=27.5mg`
`=27.5xx10^(-3)g`
`"Mole fraction of "N_(2)=("Moles of "N_(2))/("Moles of "H_(2)O+"Moles of "N_(2))`
`("Moles of "N_(2))/("Moles of "H_(2)O)" "(becauseN_(2)lt ltH_(2)O)`
`=((27.5xx10^(-3))/(28))/(180/(18))=1xx10^(-5)`